Canna-Chemistry

#1

Hey there canna fam! Just starting a new topic for the other back yard organic chemists out there.

I have some new steam distillation and extraction glassware on the way and figured it was as good a time as any to get some discussion going on it.

If anyone else would like to learn I’m here to help.

Here are things I am currently capable of teaching or assisting with with my current equipment using short path, vacuum, and steam distillation.

  1. Terpene distillation.
  2. Soxhlet extraction. (Makes the best and purest oil extracts I’ve ever seen or had including small batch rso using a fraction of the alcohol/solvent.)
  3. Solvent recovery.
  4. Distilling (or drying really) ethanol passed 95.6% to make 100% ethanol for lab and food grade solvent extractions requiring organic solvents.
  5. Making THC distillates.
  6. Making CBD distillates.
  7. Making HTFSE (terp sauce basically).
  8. Making essential oils.
  9. Purifying/purging extracts to between 90-99%.
  10. Doing it cheap without breaking the bank.
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#2

@everyone here is the formula to find the estimated concentration of particles formed in a solution/colloid made using electrolysis. (Such as ionic/colloidal silver/copper/etc)

This formula will give you the mg/l (milligrams per liter) in water which is almost equivalent to ppm. Granted ppm is a volume/volume measurement and mg/l is a mass/volume measurement they are roughly the same for this purpose.

Concentration mg/l

([molē x u]x1000)÷L

molē=Q÷F
Q=i x t i=charge/amperes t=time/seconds
F=Faraday’s constant 96485.332(59) Cmol-1

So, for simplicity we will do .5 ampere at 600 seconds (10 minutes) using copper atomic mass 63.546 u in 1 liter of water.

Q=.5x600=300
molē=300÷96485=.00311 (rounded up)
grams=.00311x63.546=.1976 (rounded down)
mg=.1976x1000=197.6
mg/l=197.6÷1=197.6 mg/l

In formula: ([.00311x63.456]x1000)÷1=197.6 mg/l